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Raise an exception if an os.stat() call on either pathname fails. All I >> want to do is drive it from one location to another. >> > > And one day your car doesn't start. The return value is the concatenation of path and any members of *paths with exactly one directory separator (os.sep) following each non-empty part except the last, meaning that the result Linux is case sensitive. –Robert Jacobs Apr 9 '15 at 14:52 But, 2nd and 3rd os.path.exists both pass True! –speedyrazor Apr 9 '15 at 14:55 Which file Source

Does anyone know about this? That doesn't mean that developers don't have access to the full filename. So the finance people's computer breaks, and someone comes to fix it for them. Browse other questions tagged php python or ask your own question. navigate here

Os.path.exists Returns False

Why should they have to learn that the magic sequence of ".XLS", > when appended to a file name, make the file work a certain way? Iyer wrote: > So, it was the extensions all the way ! This issue is now closed. Join our Network Research Panel today! _______________________________________________ Tutor maillist - [hidden email] http://mail.python.org/mailman/listinfo/tutor Bob Gailer-2 Reply | Threaded Open this post in threaded view ♦ ♦ | Report Content as

So, it was the extensions all the way ! If it breaks, maybe I go buy a service manual and fix it, or maybe I recognize that the time it would take me to learn the intricacies of the electronics All of these routes waste space, and only provide minimal advantage, but manage to provide serious breaches of understanding. They would rather have Microsoft make obfuscate things, to make it "easier" for them, than to try to understand themselves.

os.path.splitext(path)¶ Split the pathname path into a pair (root, ext) such that root + ext == path, and ext is empty or begins with Thank you. –schroeder Sep 26 '12 at 20:32 add a comment| up vote 1 down vote This may not answer your question directly, but you could go with the "try/except" method: Go to the directory and check the output of pwd. http://stackoverflow.com/questions/22359598/python-os-path-exists-not-working This is the second element of the pair returned by passing path to the function split().

Thanks, Kent _______________________________________________ Tutor maillist - [hidden email] http://mail.python.org/mailman/listinfo/tutor Tiger12506 Reply | Threaded Open this post in threaded view ♦ ♦ | Report Content as Inappropriate ♦ ♦ Re: [OT] Thre are no "broken hard links"... _______________________________________________ Tutor maillist - [hidden email] http://mail.python.org/mailman/listinfo/tutor Iyer Reply | Threaded Open this post in threaded view ♦ ♦ | Report Content as Inappropriate Note : if i run the command from terminal.app it is working. –Ramesh R C Dec 15 '14 at 10:51 @RameshRC Where exactly is your directory mounted? to avoid visiting certain parts of the tree. (The object referred to by names must be modified in place, using del or slice assignment.) Note Symbolic links to directories are

Os.path.isdir Not Working

This is an unfortunate side-effect. http://python.6.x6.nabble.com/os-path-exists-path-returns-false-when-the-path-actually-exists-td1701865.html How to stop a Linux process for later execution swapping-out its memory Do the Infinity Gems spell out Thanos? Os.path.exists Returns False in your own image. File Exists Python Please donate.

Hey ~ you wouldn't even have to know which channel you want to watch. Most people don't realize where they are. Is Dumbledore partially at fault for how Tom Riddle turned out? This function implements the underlying comparison used by samefile() and sameopenfile(). Python Check If Directory Exists

  • Is it case sensitive?
  • Because they want "ease of use", I must buy bigger hard drives, and more ram.
  • Because Microsoft has determined that media is more important to the mass population than performance, I have to fight to get my Windows installation to stop initiating the time-consuming Autoplay feature,
  • Give me a damn RFC.
  • os.path.join(path, *paths)¶ Join one or more path components intelligently.
  • I see that > hiding of the technical details as an improvement, not a hindrance.
  • On 31/07/07, Iyer <[hidden email]> wrote: > os.path.exists("c:/winnt/file_name") > > Nope, even, with the use of forward slashes in the path, it still returns > false > > What am I

All you would have to do is know *what* you want to watch. I expect them to overlook it. I do not expect > them to understand *why* the magic sequence of .xls causing this file to > open in Excel. http://europrolink.com/not-working/path-variable-not-working-windows-7.php I expect them to accept them.

php python share|improve this question asked Dec 15 '14 at 9:58 Ramesh R C 88211 Surely you're mounting it at ~/z, not /Volumes/, so you should be checking there? So they hide them by default in the GUI. What is going on?

Is that good enough?

I can all but guarantee that the issue is with your input file being improperly formatted. They are better > placed in a blog somewhere, or more efficiently, in a zip file of ASCII text > as small and as neat as possible. Then you have no need to check whether or not the file exists yourself. Availability: Unix.

Functions such as expanduser() and expandvars() can be invoked explicitly when an application desires shell-like path expansion. (See also the glob module.) Note Since different operating systems have Tiger12506 wrote: > I apologize for my bringing up these beliefs on this list. Share this Related Tips What is the use of buffering in python's built-in open() function? Check This Out New in version 2.3.

To visit linked directories you must identify them with os.path.islink(file) and os.path.isdir(file), and invoke walk() as necessary. Or the carriage returns. \r means return to the beginning of the line, \n means go to the next line. Because it's a good idea. Or it may not differentiate between symbolic links and actual files.